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NCERT Exemplar · Q11

Q.If the density of a solution is 3.12 g mL−13.12\ \text{g mL}^{-1}, the mass of 1.5 mL solution in significant figures is ______.

(i) 4.7 g
(ii) 4680×10−34680 \times 10^{-3} g
(iii) 4.680 g
(iv) 46.80 g
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Multiply density by volume, then round the result to match the least number of significant figures in the given data (two). The mass is 4.7 g.

Why significant figures matter in multiplication

When you multiply measured quantities, the precision of your answer cannot exceed the precision of your least-precise input. Significant figures capture this idea: they tell us how many digits in a number are meaningful based on the measurement's uncertainty.

The rule for multiplication and division is straightforward: the result should have as many significant figures as the measurement with the fewest significant figures.

Here we're using the relationship between density, mass, and volume:

Mass=Density×Volume\text{Mass} = \text{Density} \times \text{Volume}

Let's identify the significant figures in our given data and then calculate.

Step-by-step calculation

  1. Count significant figures in the given values

    • Density: 3.12 g mL−13.12\ \text{g mL}^{-1} has 3 significant figures (all non-zero digits count)
    • Volume: 1.5 mL1.5\ \text{mL} has 2 significant figures (the trailing zero after the decimal would need to be written explicitly to count)
  2. Perform the raw calculation

Mass=3.12×1.5=4.68 g\text{Mass} = 3.12 \times 1.5 = 4.68\ \text{g}

  1. Apply the significant figure rule

    The limiting factor is the volume with only 2 significant figures. Therefore, our answer must be rounded to 2 significant figures.

    4.68 g4.68\ \text{g} rounded to 2 significant figures becomes 4.7 g4.7\ \text{g}. …

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