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Example · Example 1

Q.Explain, with electron-dot representation, how the ionic bond in sodium chloride (NaCl\text{NaCl}) is formed starting from neutral sodium and chlorine atoms. Why does this transfer of an electron lead to a stable compound?

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Sodium has the electron configuration 2,8,12,8,1, with a single, loosely-held electron in its outermost shell; chlorine has the configuration 2,8,72,8,7, one electron short of a stable octet. Sodium's one valence electron is transferred completely to chlorine. Sodium becomes Na+\text{Na}^+ with the stable configuration 2,82,8 (matching neon), while chlorine becomes Cl−\text{Cl}^- with the stable configuration 2,8,82,8,8 (matching argon). Both ions now have a full outer octet, a lower-energy, more stable arrangement than either neutral atom had. The oppositely charged Na+\text{Na}^+ and Cl−\text{Cl}^- ions then attract each other electrostatically, and this attraction — repeated throughout a huge, ordered three-dimensional lattice, not just between one pair of ions — is the ionic bond that holds solid NaCl\text{NaCl} together. [!ANSWER] The electron transfer gives both ions stable, complete octets, and the resulting electrostatic attraction between Na+\text{Na}^+ and Cl−\text{Cl}^- constitutes the ionic bond; this lattice attraction is why NaCl\text{NaCl} is a stable, high-melting solid.

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