Skip to content
Example · Example 2

Q.Magnesium oxide (MgO\text{MgO}) has a much higher lattice enthalpy than sodium chloride (NaCl\text{NaCl}), even though both crystallise in the same rock-salt structure. Explain this difference in terms of ionic charge and ionic size.

West Bengal WbchseTextbookSubjectiveImportance★★★★★est
6% · 2/33 Questions
✓ Free question

Lattice enthalpy is governed, to a good first approximation, by Coulomb's law applied to the ions in the crystal: U∝Q+Q−r++r−U \propto \dfrac{Q_+ Q_-}{r_+ + r_-}. Two factors distinguish MgO\text{MgO} from NaCl\text{NaCl}. First, charge: Na+\text{Na}^+ and Cl−\text{Cl}^- each carry a single unit of charge, so Q+Q−=1Q_+Q_- = 1; Mg2+\text{Mg}^{2+} and O2−\text{O}^{2-} each carry two units of charge, so Q+Q−=4Q_+Q_- = 4 — a fourfold increase in the numerator of the Coulomb expression from charge alone. Second, size: Mg2+\text{Mg}^{2+} and O2−\text{O}^{2-} are both smaller ions than Na+\text{Na}^+ and Cl−\text{Cl}^- respectively, so r++r−r_+ + r_- is also smaller for MgO\text{MgO}, which further increases UU by shrinking the denominator. Both effects act in the same direction, so MgO\text{MgO}'s lattice enthalpy (≈3800 kJ mol−1\approx 3800\ \text{kJ mol}^{-1}) is roughly five times NaCl\text{NaCl}'s (≈780 kJ mol−1\approx 780\ \text{kJ mol}^{-1}), even though both compounds adopt the identical rock-salt crystal structure. [!ANSWER] The much higher charge product (2+×2−=42^+\times2^-=4 versus 1+×1−=11^+\times1^-=1) together with the smaller ionic radii of Mg2+\text{Mg}^{2+} and O2−\text{O}^{2-} together make MgO\text{MgO}'s lattice enthalpy far larger than NaCl\text{NaCl}'s.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.