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Example · Example 5

Q.Draw the Lewis structure of carbon dioxide (CO2\text{CO}_2), showing all bonding and lone pairs, and verify that the octet rule is satisfied on every atom.

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CO2\text{CO}_2 has 4+6+6=164 + 6 + 6 = 16 valence electrons in total. Placing carbon centrally and forming a double bond to each oxygen uses 4×2=84 \times 2 = 8 electrons in bonding pairs, leaving 16−8=816 - 8 = 8 electrons, which are placed as two lone pairs on each oxygen (2×4=82 \times 4 = 8 electrons). The resulting structure is O=C=O\text{O}=\text{C}=\text{O}. Checking octets: carbon is surrounded by two double bonds, i.e. 2×2=42\times2=4 bonding pairs =8= 8 electrons, a complete octet, with zero lone pairs on carbon; each oxygen is surrounded by one double bond (counted as 2 bonding pairs =4=4 electrons around that oxygen) plus two lone pairs (44 electrons), for 88 electrons total, also a complete octet. All 16 valence electrons are accounted for and every atom has a full octet, so this Lewis structure is valid and, being linear and symmetric, matches CO2\text{CO}_2's known linear molecular shape. [!ANSWER] O=C=O\text{O}=\text{C}=\text{O}, carbon with no lone pairs and each oxygen with two lone pairs, satisfies the octet rule on every atom using all 16 valence electrons.

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