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Exercise: Algebra of Complex Numbers · Q12

Q.If z1=3+2iz_1=3+2i and z2=1−iz_2=1-i, verify that z1z2‾=zˉ1 zˉ2\overline{z_1z_2}=\bar z_1\,\bar z_2.

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z1z2=(3+2i)(1−i)=3−3i+2i−2i2=3−i+2=5−iz_1z_2=(3+2i)(1-i)=3-3i+2i-2i^2=3-i+2=5-i, so z1z2‾=5+i\overline{z_1z_2}=5+i. Separately, zˉ1=3−2i, zˉ2=1+i\bar z_1=3-2i,\ \bar z_2=1+i, so zˉ1zˉ2=(3−2i)(1+i)=3+3i−2i−2i2=3+i+2=5+i\bar z_1\bar z_2=(3-2i)(1+i)=3+3i-2i-2i^2=3+i+2=5+i. Both computations give …

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