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Exercise: Algebra of Complex Numbers · Q11

Q.Evaluate i37+1i67i^{37}+\dfrac{1}{i^{67}}.

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i37i^{37}: 37=4(9)+137=4(9)+1, so i37=i1=ii^{37}=i^1=i. For 1i67=i−67\dfrac1{i^{67}}=i^{-67}: since i−1=−ii^{-1}=-i, i−67=(i−1)67=(−i)67=(−1)67i67=−i67i^{-67}=(i^{-1})^{67}=(-i)^{67}=(-1)^{67}i^{67}=-i^{67}. Now 67=4(16)+367=4(16)+3, so i67=i3=−ii^{67}=i^3=-i …

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