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Example · Example 6

Q.If P(A)=0.4P(A) = 0.4, P(B)=0.5P(B) = 0.5, and AA, BB are mutually exclusive events, find P(A∪B)P(A \cup B) and P(A∩B)P(A \cap B).

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Since AA and BB are mutually exclusive, by definition A∩B=ϕA \cap B = \phi, so P(A∩B)=0P(A \cap B) = 0 (the impossible event has probability 00, consistent with Axiom 1 giving P(ϕ)≥0P(\phi) \ge 0 and P(ϕ)+P(S)=P(S)P(\phi)+P(S)=P(S) forcing P(ϕ)=0P(\phi)=0). By Axiom 3, since A,BA, B are mutua …

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