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Example · Example 7

Q.If P(A)=0.6P(A) = 0.6 for an event AA, find P(A′)P(A'), the probability of 'not AA'.

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By the complement rule, derived from A∪A′=SA \cup A' = S and A∩A′=ϕA \cap A' = \phi together with Axioms 2 and 3, P(A′)=1−P(A)P(A') = 1 - P(A). Substituting P(A)=0.6P(A) = 0.6: P(A′)=1−0.6=0.4P(A') = 1 - 0.6 = 0.4. As a c …

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