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Exercise: Axiomatic Probability · Q21

Q.Can the following be a valid probability assignment for S={1,2,3}S = \{1, 2, 3\}: P(1)=0.5P(1) = 0.5, P(2)=0.6P(2) = 0.6, P(3)=−0.1P(3) = -0.1? Justify your answer using the axioms of probability.

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Axiom 1 requires P(E)≥0P(E) \ge 0 for every event, including simple events. Here P(3)=−0.1<0P(3) = -0.1 < 0, which directly violates Axiom 1, regardless of the other two values. It is worth noting that P(1)+P(2)+P(3)=0.5+0.6−0.1=1.0P(1)+P(2)+P(3) = 0.5+0.6-0.1 = 1.0, so the assignment does satisfy the 'total equals 11' requirement of Axiom 2 — but Axiom 2 is not enough on its own; Axiom 1 must hold for every individual event as well, and a negative probability is never a …

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