Skip to content
Exercise: Axiomatic Probability · Q20

Q.A probability function assigns P(1)=0.1P(1) = 0.1, P(2)=0.2P(2) = 0.2, P(3)=0.3P(3) = 0.3, P(4)=0.4P(4) = 0.4 to the outcomes of S={1,2,3,4}S = \{1, 2, 3, 4\}. Verify that this satisfies the axioms of probability, and find the probability of the event 'the outcome is even'.

West Bengal WbchseTextbookSubjectiveImportance★★★★★
70% · 23/33 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Axiom 1 requires every probability ≥0\ge 0: here 0.1,0.2,0.3,0.40.1, 0.2, 0.3, 0.4 are all positive, so Axiom 1 holds. Axiom 2 requires P(S)=1P(S)=1: since {1},{2},{3},{4}\{1\},\{2\},\{3\},\{4\} are disjoint with union SS, Axiom 3 gives P(S)=P(1)+P(2)+P(3)+P(4)=0.1+0.2+0.3+0.4=1.0P(S)=P(1)+P(2)+P(3)+P(4)=0.1+0.2+0.3+0.4=1.0, matching Axiom 2. So the assignment is a valid probability function. The event 'outcome is even' is ${2,4} …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.