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Example · Example 2

Q.A steel railway rail is 20 m20\ \text{m} long at 10 ∘C10\,^\circ\text{C}. If the rail is heated to 40 ∘C40\,^\circ\text{C} on a hot afternoon, find the increase in its length. Take the coefficient of linear expansion of steel as α=1.2×10−5 ∘C−1\alpha = 1.2\times10^{-5}\ {}^\circ\text{C}^{-1}.

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✓ Free question

Given: L0=20 mL_0 = 20\ \text{m}, ΔT=40−10=30 ∘C\Delta T = 40 - 10 = 30\,^\circ\text{C}, α=1.2×10−5 ∘C−1\alpha = 1.2\times10^{-5}\ {}^\circ\text{C}^{-1}.

Using ΔL=L0 α ΔT\Delta L = L_0\,\alpha\,\Delta T:

ΔL=20×1.2×10−5×30=7.2×10−3 m\Delta L = 20 \times 1.2\times10^{-5} \times 30 = 7.2\times10^{-3}\ \text{m}

✓Final answer

The rail's length increases by 7.2×10−3 m=7.2 mm7.2\times10^{-3}\ \text{m} = 7.2\ \text{mm}.

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