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Example · Example 3

Q.200 g200\ \text{g} of water at 80 ∘C80\,^\circ\text{C} is poured into 300 g300\ \text{g} of water at 20 ∘C20\,^\circ\text{C} inside a calorimeter of negligible heat capacity. Find the common temperature reached by the mixture once thermal equilibrium is established.

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By the principle of calorimetry, heat lost by the hot water equals heat gained by the cold water (the calorimeter's heat capacity is negligible, and the specific heat capacity cc of water cancels from both sides since it is the same substance):

m1(T1−Tf)=m2(Tf−T2)m_1(T_1 - T_f) = m_2(T_f - T_2)

200(80−Tf)=300(Tf−20)200(80 - T_f) = 300(T_f - 20)

16000−200Tf=300Tf−600016000 - 200T_f = 300T_f - 6000 …

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