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Exercise: Maxima and Minima · Q27

Q.A rectangle has a fixed perimeter of 40 m40\ \text{m}. Express its area as a function of one side, and find the dimensions of the rectangle for which the area is maximum.

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Let the two adjacent sides of the rectangle be xx and yy. Perimeter =2(x+y)=40  ⟹  x+y=20  ⟹  y=20−x=2(x+y)=40 \implies x+y=20 \implies y=20-x.

Area as a function of xx alone: A(x)=xy=x(20−x)=20x−x2\quad A(x)=xy=x(20-x)=20x-x^2, for 0<x<200<x<20.

A′(x)=20−2x.A′(x)=0  ⟹  x=10.A'(x)=20-2x. \qquad A'(x)=0 \implies x=10.

A′′(x)=−2<0  ⟹  maximum at x=10.A''(x)=-2<0 \implies \text{maximum at } x=10. …

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