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Exercise: Maxima and Minima · Q28

Q.An open box is to be made from a square piece of cardboard of side 18 cm18\ \text{cm} by cutting equal squares of side xx from each corner and folding up the sides. Find the value of xx for which the volume of the box is maximum, and find this maximum volume.

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Cutting a square of side xx from each corner of the 18 cm×18 cm18\ \text{cm}\times18\ \text{cm} sheet leaves a base of side (18−2x)(18-2x) and height xx after folding, so

V(x)=x(18−2x)2,0<x<9.V(x)=x(18-2x)^2, \qquad 0<x<9.

Expanding, V(x)=324x−72x2+4x3V(x)=324x-72x^2+4x^3, so

V′(x)=324−144x+12x2=12(x2−12x+27)=12(x−3)(x−9).V'(x)=324-144x+12x^2=12(x^2-12x+27)=12(x-3)(x-9). …

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