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Exercise: Composite Functions · Q22

Q.If f(x)=3x−5f(x) = 3x - 5 and (f∘g)(x)=6x+1(f \circ g)(x) = 6x + 1, find g(x)g(x).

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(f∘g)(x)=f(g(x))=3 g(x)−5(f\circ g)(x) = f(g(x)) = 3\,g(x) - 5. This is given to equal 6x+16x+1:

3 g(x)−5=6x+1  ⟹  3 g(x)=6x+6  ⟹  g(x)=2x+23\,g(x) - 5 = 6x+1 \implies 3\,g(x) = 6x+6 \implies g(x) = 2x+2 …

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