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Question 23 of 32

Q.A TV tower is 120 m high. How much more height is to be added to it if its coverage range is to become double? OR Draw a neat diagram of Amplitude Modulated Wave. Write down the formula of 'Modulation Index'.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2019Subjective· 2mImportance★★★★★
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Since the line-of-sight range d=2Rhd=\sqrt{2Rh}, doubling dd requires hh to become 4 times, i.e. the height must increase from 120 m to 480 m — an addition of 360 m.

The maximum line-of-sight range of a TV tower of height hh (radius of Earth RR) is

d=2Rhd = \sqrt{2Rh}

For the given tower, d1=2Rh1d_1=\sqrt{2Rh_1} with h1=120h_1=120 m. To double the range, d2=2d1d_2 = 2d_1:

d22=4d12  ⟹  2Rh2=4(2Rh1)  ⟹  h2=4h1=4×120=480 md_2^2 = 4d_1^2 \implies 2Rh_2 = 4(2Rh_1) \implies h_2 = 4h_1 = 4\times120 = 480\ \text{m} …

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