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Q.A TV tower is 120 m high. How much more height of the tower is to be increased to it if its coverage range is doubled? OR Find the length of the dipole antenna for the carrier signal of frequency 3×10⁸ Hz.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2025Subjective· 2mImportance★★★★★
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Since range d = √(2Rh), doubling d requires quadrupling h; from 120 m to 480 m, an increase of 360 m.

The line-of-sight (LOS) range from a transmitting antenna of height h (earth radius R) is

d=2Rh ⇒ d2=2Rh ⇒ h∝d2d=\sqrt{2Rh}\ \Rightarrow\ d^2 = 2Rh\ \Rightarrow\ h\propto d^2

If the range is doubled (d′=2dd' = 2d):

h′=h(d′d)2=h×4=4h=4×120=480 mh'=h\left(\dfrac{d'}{d}\right)^2=h\times 4=4h=4\times120=480\ m …

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