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Exercise · Q16

Q.Two resistors of 6 Ω6\ \Omega and 3 Ω3\ \Omega are connected in parallel. Find their equivalent resistance.

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For two resistors R1=6 ΩR_1=6\ \Omega and R2=3 ΩR_2=3\ \Omega in parallel,

1Rp=1R1+1R2=16+13=16+26=36=12\frac{1}{R_p} = \frac{1}{R_1}+\frac{1}{R_2} = \frac{1}{6}+\frac{1}{3} = \frac{1}{6}+\frac{2}{6} = \frac{3}{6} = \frac{1}{2}

Rp=2 ΩR_p = 2\ \Omega …

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