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Numerical · Q31

Q.A wire of length 5 m5\ \text{m} and uniform cross-sectional area 1×10−6 m21 \times 10^{-6}\ \text{m}^2 has a resistance of 2 Ω2\ \Omega. Calculate

(a) the resistivity and
(b) the conductivity of the material. If a potential difference of 4 V4\ \text{V} is applied across the wire's ends, find
(c) the current flowing through it and
(d) the current density.
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Given l=5 ml=5\ \text{m}, A=1×10−6 m2A=1\times10^{-6}\ \text{m}^2, R=2 ΩR=2\ \Omega, applied V=4 VV=4\ \text{V}.

  1. Resistivity:

    ρ=RAl=2×1×10−65=4×10−7 Ω m\rho = \frac{RA}{l} = \frac{2\times1\times10^{-6}}{5} = 4\times10^{-7}\ \Omega\,\text{m}

  2. Conductivity:

    σ=1ρ=14×10−7=2.5×106 S/m\sigma = \frac{1}{\rho} = \frac{1}{4\times10^{-7}} = 2.5\times10^6\ \text{S/m}

  3. Current:

    I=VR=42=2 AI = \frac{V}{R} = \frac{4}{2} = 2\ \text{A}

  4. Current density: …

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