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Question 3 of 19

Q.If A,B,CA, B, C are angles of a triangle such that x=cis⁡Ax = \operatorname{cis} A, y=cis⁡By = \operatorname{cis} B, z=cis⁡Cz = \operatorname{cis} C, then find the value of xyzxyz.

Yanam BieapBIEAP Intermediate Board 2018Subjective· 2mImportance★★★★★
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xyz=cis⁡(A+B+C)xyz = \operatorname{cis}(A+B+C), and since A+B+C=πA+B+C=\pi for a triangle, this equals cis⁡π=−1\operatorname{cis}\pi = -1.

Given x=cis⁡Ax=\operatorname{cis}A, y=cis⁡By=\operatorname{cis}B, z=cis⁡Cz=\operatorname{cis}C. Using the product rule cis⁡θ1⋅cis⁡θ2=cis⁡(θ1+θ2)\operatorname{cis}\theta_1\cdot\operatorname{cis}\theta_2 = \operatorname{cis}(\theta_1+\theta_2): …

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