Find the complex conjugate of (3 + 4i)(2 - 3i). – Class 12 Mathematics

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(3 + 4i)(2 - 3i)

Yanam BieapBIEAP Intermediate Board 2020Subjective· 2mImportance★★★★★

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Multiply the two complex numbers using $i^2=-1$ , then flip the sign of the imaginary part to get the conjugate.

Expand the product:

$(3+4i)(2-3i) = 3(2) + 3(-3i) + 4i(2) + 4i(-3i) = 6 - 9i + 8i - 12i^2$

Since $i^2=-1$ , we get $-12i^2 = 12$ :

$= 6 + 12 - 9i + 8i = 18 - i$

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Q.Find the complex conjugate of $(3 + 4i)(2 - 3i)$ .