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Question 15 of 19

Q.Find a square root of the complex number 3+4i3+4i.

Yanam BieapBIEAP Intermediate Board 2026Subjective· 2mImportance★★★★★
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Write 3+4i=x+iy\sqrt{3+4i}=x+iy, square both sides, match real/imaginary parts, and use the modulus as a third equation to pin down x,yx,y.

Let 3+4i=x+iy\sqrt{3+4i}=x+iy where x,yx,y are real. Squaring,

x2−y2+2ixy=3+4i.x^2-y^2+2ixy = 3+4i.

Comparing real and imaginary parts:

x2−y2=3and2xy=4⇒xy=2.x^2-y^2=3 \qquad\text{and}\qquad 2xy=4 \Rightarrow xy=2.

A third relation comes from equating moduli, ∣x+iy∣2=∣3+4i∣|x+iy|^2=|3+4i|:

x2+y2=32+42=25=5.x^2+y^2=\sqrt{3^2+4^2}=\sqrt{25}=5.

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