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Question 9 of 19

Q.Find the square root of the complex number 7+24i7 + 24i.

Yanam BieapBIEAP Intermediate Board 2023Subjective· 2mImportance★★★★★
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Write 7+24i=x+iy\sqrt{7+24i}=x+iy, square both sides, match real and imaginary parts, and solve for x,yx,y using the modulus as a third equation.

Let 7+24i=x+iy\sqrt{7+24i} = x+iy where x,yx,y are real. Squaring,

x2−y2+2ixy=7+24i.x^2 - y^2 + 2ixy = 7+24i.

Comparing real and imaginary parts:

x2−y2=7and2xy=24⇒xy=12.x^2-y^2 = 7 \qquad \text{and} \qquad 2xy = 24 \Rightarrow xy = 12.

A third relation comes from equating moduli: ∣x+iy∣2=∣7+24i∣|x+iy|^2 = |7+24i|, i.e.

x2+y2=72+242=49+576=625=25.x^2+y^2 = \sqrt{7^2+24^2} = \sqrt{49+576} = \sqrt{625} = 25.

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