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Exercises · 11.11

Q.What is the state of hybridisation of carbon in

(a) CO3^2–
(b) diamond
(c) graphite?
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Step 1 - (a) CO32−\text{CO}_3^{2-}

Carbon is bonded to three oxygen atoms with no lone pair on carbon (3 sigma bonds plus a delocalised pi system across all three C-O bonds by resonance); three electron domains around carbon means sp2sp^2 hybridisation, giving the trigonal planar shape (120∘120^\circ bond angles) observed for the carbonate ion.

Step 2 - (b) Diamond

Each carbon atom is bonded to four other carbon atoms by single (sigma) bonds arranged tetrahedrally; four electron domains, no lone pair, means sp3sp^3 hybridisation (bond angle 109.5∘109.5^\circ), extending through the whole 3-D lattice.

Step 3 - (c) Graphite …

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