Skip to content
Question

Q.The value of Δ=∣422579792953∣\Delta = \begin{vmatrix} 42 & 2 & 5 \\ 79 & 7 & 9 \\ 29 & 5 & 3 \end{vmatrix} is : (A) 00 (B) 11 (C) −3-3 (D) −15-15

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Cofactor expansion along row 1 yields 00, so Δ=0\Delta=0.

∣a1a2a3b1b2b3c1c2c3∣=a1(b2c3−b3c2)−a2(b1c3−b3c1)+a3(b1c2−b2c1)\begin{vmatrix}a_1&a_2&a_3\\b_1&b_2&b_3\\c_1&c_2&c_3\end{vmatrix}=a_1(b_2c_3-b_3c_2)-a_2(b_1c_3-b_3c_1)+a_3(b_1c_2-b_2c_1)

  1. Δ=∣422579792953∣\Delta=\begin{vmatrix}42&2&5\\79&7&9\\29&5&3\end{vmatrix}.
  2. 42(7⋅3−9⋅5)=42(21−45)=42(−24)=−100842(7\cdot3-9\cdot5)=42(21-45)=42(-24)=-1008. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.