Skip to content
Question

Q.Case Study – 2 In number theory, it is often important to find factors of an integer N. The number N has two trivial factors, namely 1 and N. Any other factor, if exists, is called non-trivial factor of N. Naresh has plotted a graph of some constraints (linear inequations) with points A(0,50)A(0, 50), B(20,40)B(20, 40), C(50,100)C(50, 100), D(0,200)D(0, 200) and E(100,0)E(100, 0). This graph is constructed using three non-trivial constraints and two trivial constraints. One of the non-trivial constraints is x+2y≥100x + 2y \geq 100. The graph plots the constraint lines through the points A(0,50)A(0, 50), B(20,40)B(20, 40), C(50,100)C(50, 100), D(0,200)D(0, 200) and E(100,0)E(100, 0), with two candidate feasible regions labelled R1R_1 and R2R_2. Based on the above information, answer the following questions :

(i) What are the two trivial constraints ? [1]
(ii)
(a) If R1R_1 is the feasible region, then what are the other two non-trivial constraints ? [2]
(OR)
(b) If R2R_2 is the feasible region, then what are the other two non-trivial constraints ? [2]
(iii) If R1R_1 is the feasible region, then find the maximum value of the objective function z=5x+2yz = 5x + 2y. [1]
CBSECBSE Class XII Board 2024Subjective· 4mImportance★★★★★
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Trivial constraints are x,y≥0x,y\ge0. For R1R_1 the extra constraints are 2x−y≤0, 2x+y≤2002x-y\le0,\ 2x+y\le200. Evaluating z=5x+2yz=5x+2y at R1R_1's corners gives a maximum of 450450 at C(50,100)C(50,100).

In an LPP the non-negativity restrictions x≥0,y≥0x\ge0,y\ge0 are the "trivial" constraints; other inequalities are "non-trivial." By the corner-point method, the optimum of a linear objective over a bounded feasible region occurs at a vertex — evaluate zz at every corner and pick the largest.

Given points A(0,50),B(20,40),C(50,100),D(0,200),E(100,0)A(0,50),B(20,40),C(50,100),D(0,200),E(100,0) and one non-trivial constraint x+2y≥100x+2y\ge100.

(i) The two trivial constraints are the non-negativity conditions: x≥0x\ge0 and y≥0y\ge0.

(ii) The other two non-trivial boundary lines pass through the given points. The line through the origin and C(50,100)C(50,100) is y=2xy=2x, i.e. 2x−y=02x-y=0; the line through D(0,200)D(0,200) and E(100,0)E(100,0) is x100+y200=1\dfrac{x}{100}+\dfrac{y}{200}=1, i.e. 2x+y=2002x+y=200.

  1. (a) If R1R_1 is the feasible region: 2x−y≤02x-y\le0 and 2x+y≤2002x+y\le200 (together with x+2y≥100x+2y\ge100 and x,y≥0x,y\ge0). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.