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Q.The mean weekly sales of a 4-wheeler was 50 units per agency in 20 agencies. After an advertising campaign, the mean weekly sales increased to 55 units per agency with standard deviation of 10 units. Test whether the advertising campaign was successful. [Given 5=2.24\sqrt{5} = 2.24, t19(0.05)=1.729t_{19}(0.05) = 1.729]

CBSECBSE Class XII Board 2024Subjective· 3mImportance★★★★★
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With t=55−5010/20=5=2.24>1.729t=\dfrac{55-50}{10/\sqrt{20}}=\sqrt5=2.24>1.729, reject H0H_0 — the campaign significantly raised sales.

One-sample tt-test: t=xˉ−μ0S/nt=\dfrac{\bar{x}-\mu_0}{S/\sqrt{n}}, degrees of freedom =n−1=n-1, where xˉ\bar{x} is the sample mean, μ0\mu_0 the hypothesised mean, SS the sample standard deviation and nn the sample size. Reject H0H_0 (one-tailed) if t>tn−1(α)t>t_{n-1}(\alpha).

Given μ0=50, xˉ=55, n=20, S=10\mu_0=50,\ \bar{x}=55,\ n=20,\ S=10.

  1. State hypotheses (one-tailed): H0:μ=50H_0:\mu=50 (campaign not successful) vs Hα:μ>50H_\alpha:\mu>50 (campaign successful).
  2. Standard error: Sn=1020\dfrac{S}{\sqrt{n}}=\dfrac{10}{\sqrt{20}}. …

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