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Q.The function f(x)=x2−x+1f(x) = x^2 - x + 1 is : (A) increasing in (0,1)(0, 1) (B) decreasing in (0,1)(0, 1) (C) increasing in (0,12)(0, \frac{1}{2}) and decreasing in (12,1)(\frac{1}{2}, 1) (D) increasing in (12,1)(\frac{1}{2}, 1) and decreasing in (0,12)(0, \frac{1}{2})

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
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The turning point is at x=12x=\tfrac12; ff decreases on (0,12)(0,\tfrac12) and increases on (12,1)(\tfrac12,1).

ff is increasing where f′(x)>0f'(x)>0 and decreasing where f′(x)<0f'(x)<0.

  1. f(x)=x2−x+1⇒f′(x)=2x−1f(x)=x^2-x+1\Rightarrow f'(x)=2x-1.
  2. f′(x)=0⇒x=12f'(x)=0\Rightarrow x=\tfrac12 (the critical point). …

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