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Q.In a 1 km race, player P beats player Q by 18 metres or 9 seconds. What is P's time to complete the race ? (A) 512 seconds (B) 502 seconds (C) 491 seconds (D) 481 seconds

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
✓ Free question

Q covers the gap of 18 m in 9 s (speed 2 m/s); P finishes the race exactly when Q reaches the 982 m mark, which takes 491 s.

speed=distancetime\text{speed}=\dfrac{\text{distance}}{\text{time}}, and "P beats Q by dd metres or tt seconds" means Q runs the last dd metres in tt seconds.

  1. From "18 metres or 9 seconds", Q takes 99 s to run 1818 m, so Q's speed is vQ=189=2v_Q=\dfrac{18}{9}=2 m/s.
  2. When P completes the full 10001000 m, Q is 1818 m behind, i.e. Q has run 1000−18=9821000-18=982 m.
  3. Both finish-of-P and Q-at-982 m happen at the same instant, so P's time equals the time Q needs for 982982 m: t=9822=491t=\dfrac{982}{2}=491 s.
✓Final answer

(C) 491 seconds

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