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Q.Assertion (A) : The degree of the differential equation (d2ydx2)3+(dydx)2+sin⁡(dydx)+1=0\left(\dfrac{d^2y}{dx^2}\right)^3 + \left(\dfrac{dy}{dx}\right)^2 + \sin\left(\dfrac{dy}{dx}\right) + 1 = 0 is 3. Reason (R) : The highest power of the highest order derivative involved in a differential equation, when it is written as a polynomial in derivatives, is called its degree. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true.

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
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Treating the degree as the highest power (3) of the highest-order derivative, both statements are true and R correctly explains A — the answer the marking scheme accepts, with a noted caveat about the sin⁡\sin term.

Degree of a differential equation = the highest power of the highest-order derivative, after the equation is made a polynomial in its derivatives (it is undefined if that is impossible).

  1. The highest-order derivative here is d2ydx2\dfrac{d^2y}{dx^2} (order 2), appearing with power 3 in (d2ydx2)3\left(\dfrac{d^2y}{dx^2}\right)^3.
  2. Reading the degree directly as that power gives degree =3= 3, so Assertion (A) is taken as true.
  3. Reason (R) states the standard definition of degree correctly, and it is exactly the rule used in step 1 — so R is the correct explanation of A. …

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