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Q.A machine costing ₹ 2,00,000 has effective life of 7 years and its scrap value is ₹ 30,000. What amount should the company put into a sinking fund earning 5% p.a. so that it can replace the machine after its useful life ? Assume that a new machine will cost ₹ 3,00,000 after 7 years. [Given : (1.05)7=1.407(1.05)^7 = 1.407]

CBSECBSE Class XII Board 2024Subjective· 3mImportance★★★★★
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The required accumulated amount is ₹2,70,000\text{₹}2{,}70{,}000; using the sinking-fund formula with i=0.05, n=7, (1.05)7=1.407i=0.05,\ n=7,\ (1.05)^7=1.407, the annual deposit is ₹33,169.5333{,}169.53.

Sinking fund (ordinary annuity): A=R[(1+i)n−1i]A=R\left[\dfrac{(1+i)^n-1}{i}\right], where AA is the amount to accumulate, RR the periodic deposit, ii the periodic rate, nn the number of periods.

  1. Amount to accumulate: new machine will cost ₹3,00,000; the old machine fetches scrap ₹30,000, so the fund must provide A=3,00,000−30,000=₹2,70,000.A=3{,}00{,}000-30{,}000=\text{₹}2{,}70{,}000.
  2. Rate per year i=5%=0.05i=5\%=0.05; number of years n=7n=7.
  3. Sinking-fund relation: 2,70,000=R[(1.05)7−10.05].2{,}70{,}000=R\left[\dfrac{(1.05)^7-1}{0.05}\right]. …

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