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Q.In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. By how much can A beat C in the same race ? (A) 32 m (B) 28 m (C) 24 m (D) 20 m

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
✓ Free question

A:B = 100:75 and B:C = 100:96, so when A runs 100 m, C runs 72 m — A beats C by 28 m.

In a fixed-time race, distances are proportional: if A beats B by d1d_1 in a race of length LL, then distAdistB=LL−d1\dfrac{\text{dist}_A}{\text{dist}_B}=\dfrac{L}{L-d_1}. Chain the ratios A:B and B:C to get A:C.

  1. A beats B by 25 m in 100 m: when A runs 100100, B runs 100−25=75100-25=75 m.
  2. B beats C by 4 m in 100 m: when B runs 100100, C runs 100−4=96100-4=96 m.
  3. Find C's distance while A runs 100 m (so B runs 75 m): C=75×96100=72C = 75\times\dfrac{96}{100} = 72 m.
  4. A beats C by 100−72=28100 - 72 = 28 m.
✓Final answer

(B) 28 m

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