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Q.If for a data, n=6n = 6, Σy=84\Sigma y = 84, Σxy=108\Sigma xy = 108, Σx2=70\Sigma x^2 = 70 and Σx=0\Sigma x = 0, then the equation of the straight line trend is : (A) yc=14+1.54xy_c = 14 + 1.54x (B) yc=1.54+14xy_c = 1.54 + 14x (C) yc=14+3.08xy_c = 14 + 3.08x (D) yc=3.08+14xy_c = 3.08 + 14x

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Since Σx=0\Sigma x=0, a=Σy/n=14a=\Sigma y/n=14 and b=Σxy/Σx2=1.54b=\Sigma xy/\Sigma x^2=1.54, so yc=14+1.54xy_c=14+1.54x.

Least-squares trend yc=a+bxy_c=a+bx. When Σx=0\Sigma x=0: a=Σyna=\dfrac{\Sigma y}{n} and b=ΣxyΣx2b=\dfrac{\Sigma xy}{\Sigma x^2}.

  1. Intercept: a=Σyn=846=14a = \dfrac{\Sigma y}{n} = \dfrac{84}{6} = 14. …

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