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Q.In what ratio must water be mixed with milk to gain 1623%16\dfrac{2}{3}\% on selling the mixture at cost price ? (A) 1:61 : 6 (B) 6:16 : 1 (C) 3:23 : 2 (D) 2:32 : 3

CBSECBSE Class XII Board 2024MCQ· 1mImportance★★★★★
✓ Free question

Since water is free, the profit fraction on selling at cost price equals (water)/(milk), which here is 16\tfrac16, giving water : milk =1:6=1:6.

When a mixture of water and milk is sold at the cost price of milk alone, Gain%=quantity of waterquantity of milk×100\text{Gain}\% = \dfrac{\text{quantity of water}}{\text{quantity of milk}}\times 100, because the water contributes revenue at zero cost.

  1. Convert the required gain: 1623%=503%16\dfrac{2}{3}\% = \dfrac{50}{3}\%.
  2. As a fraction: 503%=503×100=16\dfrac{50}{3}\% = \dfrac{50}{3\times 100} = \dfrac{1}{6}.
  3. Set the gain fraction equal to the ratio of water to milk: watermilk=16\dfrac{\text{water}}{\text{milk}} = \dfrac{1}{6}.
  4. Hence water : milk =1:6= 1 : 6.
✓Final answer

(A) 1:61 : 6

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