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Q.A machinist is making engine parts with axle diameter of 0.7 cm. A random sample of 10 parts shows mean diameter 0.742 cm with a standard deviation of 0.04 cm. On the basis of this sample, find if you would say that the work is inferior. (Given t9(0.05)=2.262t_9(0.05) = 2.262)

CBSECBSE Class XII Board 2025Subjective· 3mImportance★★★★★
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t=0.742−0.70.04/9=3.15t = \dfrac{0.742 - 0.7}{0.04/\sqrt{9}} = 3.15, which exceeds t9(0.05)=2.262t_9(0.05) = 2.262; reject H0H_0 — the work is inferior.

One-sample t-test: t=xˉ−μs/n−1t = \dfrac{\bar{x} - \mu}{s/\sqrt{n-1}} with n−1n-1 degrees of freedom, where xˉ\bar{x} = sample mean, μ\mu = population standard, ss = sample SD, nn = sample size.

  1. Given xˉ=0.742\bar{x} = 0.742, μ=0.7\mu = 0.7, s=0.04s = 0.04, n=10n = 10.
  2. Hypotheses: H0H_0: xˉ=μ\bar{x} = \mu (no significant difference, work is fine); H1H_1: xˉ≠μ\bar{x} \ne \mu (significant difference). …

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