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Q.A runs 32\dfrac{3}{2} times as fast as B. If A gives B a start of 40 m, how far must the winning post from the starting point be, so that A and B reach at the same time ?

CBSECBSE Class XII Board 2025Subjective· 2mImportance★★★★★
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A covers xx, B covers (x−40)(x-40) in equal time; with speed ratio 3:23:2 this gives x3=40\tfrac{x}{3} = 40, so x=120x = 120 m.

For equal time, distanceAspeedA=distanceBspeedB\dfrac{\text{distance}_A}{\text{speed}_A} = \dfrac{\text{distance}_B}{\text{speed}_B}. Let B's speed be vv; then A's speed is 32v\tfrac{3}{2}v.

  1. Let the winning post be xx metres from the start. A runs the full xx m; B, starting 40 m ahead, runs (x−40)(x - 40) m.
  2. They reach together, so their times are equal: …

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