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Q.

(a) Compute the seasonal indices by 4-year moving averages from the given data of production of paper (in thousand tons) : | Year | 2001 | 2002 | 2003 | 2004 | 2005 | 2006 | 2007 | 2008 | 2009 | 2010 | |---|---|---|---|---|---|---|---|---|---|---| | Index number | 2450 | 1470 | 2150 | 1800 | 1210 | 1950 | 2300 | 2500 | 2480 | 2680 | OR (b) Fit a straight-line trend by method of least squares for the following data : | Year | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | |---|---|---|---|---|---|---| | Production (in tons) | 210 | 225 | 275 | 220 | 240 | 235 |

CBSECBSE Class XII Board 2025Subjective· 5mImportance★★★★★
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  1. Form 4-year moving totals → 4-year averages → centre them in pairs to get the centred moving average for 2003–2008.
  2. Coding time as u=(x−2013.5)/0.5u=(x-2013.5)/0.5 gives a=14056=234.17a=\tfrac{1405}{6}=234.17, b=11570=1.64b=\tfrac{115}{70}=1.64, so Y=234.17+1.64uY = 234.17 + 1.64u.

Part (a) — 4-year centred moving averages

For an even period, compute 4-year moving totals, divide by 4 (moving average), then average consecutive pairs (centred total ÷ 2) to align with the actual year.

YearValue4-yr moving total4-yr moving avgCentred totalCentred moving avg
20012450
20021470
78701967.5
200321503625.01812.5
66301657.5
200418003435.01717.5
71101777.5
200512103592.51796.25
72601815.0
200619503805.01902.5
79601990.0
200723004297.52148.75
92302307.5
200825004797.52398.75
99602490.0
20092480
20102680
  1. 4-year moving totals (e.g. 2450+1470+2150+1800=78702450+1470+2150+1800 = 7870) are divided by 4 to get the moving averages (1967.5, 1657.5, …). …

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