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Q.The demand function of a monopolist is given by p=30+5x−3x2p = 30 + 5x - 3x^2, where xx is the number of units demanded and pp is the price per unit. The marginal revenue when 2 units are sold, is (A) ₹ 28 (B) ₹ 23 (C) ₹ 1 (D) ₹ 14

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R=px=30x+5x2−3x3R=px=30x+5x^2-3x^3, so MR=dRdx=30+10x−9x2MR=\tfrac{dR}{dx}=30+10x-9x^2; at x=2x=2, MR=₹14MR=\text{₹}14.

Revenue R(x)=p⋅xR(x)=p\cdot x; Marginal Revenue MR=dRdxMR=\dfrac{dR}{dx}.

  1. Form total revenue: R=px=(30+5x−3x2)x=30x+5x2−3x3R=px=(30+5x-3x^2)x=30x+5x^2-3x^3.
  2. Differentiate: MR=dRdx=30+10x−9x2MR=\dfrac{dR}{dx}=30+10x-9x^2. …

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