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Q.Two numbers are selected at random (without replacement) from first six positive integers. Let X denotes the smaller of the two numbers obtained. Calculate the mathematical expectation of X.

CBSECBSE Class XII Board 2025Subjective· 3mImportance★★★★★
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With 15 equally-likely pairs, P(X=k)=6−k15P(X=k)=\tfrac{6-k}{15} for k=1,…,5k=1,\dots,5; E(X)=3515=73E(X)=\tfrac{35}{15}=\tfrac{7}{3}.

E(X)=∑x P(X=x)E(X) = \sum x\,P(X=x), where XX = smaller of the two chosen numbers, and P(X=k)=favourable pairs(62)P(X=k) = \dfrac{\text{favourable pairs}}{\binom{6}{2}}.

  1. Total ways to pick 2 of 6 (without replacement, order irrelevant) =(62)=15= \binom{6}{2} = 15.
  2. X=kX = k means the smaller is kk and the other is larger; there are (6−k)(6-k) such choices. So P(X=k)=6−k15P(X=k) = \dfrac{6-k}{15}, k=1,2,3,4,5k = 1,2,3,4,5.
  3. Probability distribution and products:

| XX | 1 | 2 | 3 | 4 | 5 |

|---|---|---|---|---|---| …

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