Q.An electromagnetic wave is propagating along the -axis. At any instant, the phase difference (in radian) between the electric field () and the magnetic field () associated with the wave is (A) zero (B) (C) (D)
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Start your 14-day free trial to unlock the full solution →In a propagating electromagnetic wave, the electric and magnetic fields oscillate in phase with each other, so the phase difference is zero. The correct option is (A).
Concept and Intuition
The question tests a fundamental property of electromagnetic waves in free space. Many students carry a vague memory that and are "perpendicular" and mistakenly think that means a phase difference. But perpendicularity here refers to direction in space, not a time delay.
In a plane electromagnetic wave, both fields vary sinusoidally with position and time. Maxwell's equations demand that the time-varying electric field produces the magnetic field, and vice versa — they are coupled in such a way that their peaks and zeros occur at the same instant. There is no lag between them.
A common mistake is to confuse spatial orthogonality (the fields are perpendicular to each other and to the direction of propagation) with a phase difference. They are perpendicular in space, but they oscillate in time together — zero phase difference.
Step-by-Step Reasoning
- Recall the wave equations from Maxwell's laws In free space (no charges or currents), Maxwell's equations yield wave equations for both and . For a wave traveling along the -axis, the solutions are:
Notice the same argument appears in both. This is not an assumption — it follows directly from Faraday's law and Ampère's law.
- Why the phase must be identical Consider Faraday's law for a plane wave:
If and , then:
- Left side:
- Right side: …
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