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Question Bank (2 marks) · Q14

Q.Derive the relation μ = r_d × g_m .

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[!TLDR]

By introducing ΔID\Delta I_D into the definition of μ\mu, the definition splits into rdr_d and gmg_m, giving μ=rd×gm\mu = r_d \times g_m.

The amplification factor is defined as

μ=ΔVDSΔVGS\mu = \frac{\Delta V_{DS}}{\Delta V_{GS}}

Multiplying and dividing the right-hand side by the small change in drain current ΔID\Delta I_D (which does not change its value),

μ=ΔVDSΔVGS×ΔIDΔID\mu = \frac{\Delta V_{DS}}{\Delta V_{GS}} \times \frac{\Delta I_D}{\Delta I_D}

Re-grouping the four factors, …

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