Q.

1. Observe the following and answer the questions given below
   CH3-CH3 --U.V. light--> CH3• + CH3•
   a. Name the reactive intermediate produced.
   b. Indicate the movement of electrons by suitable arrow to produce this intermediate.
   c. Comment on stability of this intermediate produced.

Step 1. Name the intermediate (part a). CH3-CH3 --U.V. light--> CH3• + CH3•: UV light supplies the energy for homolytic cleavage of the C-C bond, and each fragment carries one unpaired electron -- so the reactive intermediate produced is the methyl free radical, CH3• (section 14.6.1).

Step 2. Electron movement (part b). Homolytic cleavage is shown using a half-headed curved ('fish-hook') arrow for each of the bond's two electrons -- one fish-hook arrow drawn from the C-C bond to one carbon, and a second fish-hook arrow drawn from the same bond to the other carbon, so that each carbon ends up with exactly one of the two originally-shared electrons. …

Applying section 14.6.1's homolytic-cleavage mechanism and free-radical stability order directl …

• Drawing a single full (double-headed) curved arrow instead of two separate fish-hook (half-headed) arrows -- homolysis specifically requires the half-headed arrow notation for single-electron movement. …