Exercises · 14.17
Q.
- Draw resonance structures of the following:
A. Phenol
A. Phenol
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Start your 14-day free trial to unlock the full solution →Step 1. Phenol, C6H5-OH, has its oxygen lone pair positioned to conjugate directly with the attached aromatic ring -- exactly the +R-donating behaviour section 14.6.6 assigns to -OH.
Step 2. Donating that lone pair into the ring (curved arrow from O's lone pair into the ring pi system, and a corresponding curved arrow shifting a ring pi bond onward) generates a resonance structure with a formal negative charge on an ORTHO ring carbon and a formal positive charge on oxygen.
Step 3. A second such donation instead places the negative charge on the PARA ring carbon (again with positive charge on oxygen). …
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