Exercises · 14.19
Q.C. Buta-1,3-diene
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
46% · 19/41 Questions
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1. Buta-1,3-diene, CH2=CH-CH=CH2, is a genuine conjugated system (two C=C double bonds separated by only one C-C single bond), so resonance theory applies directly (section 14.6.5), exactly as tested in Problem 14.10(iii) for this same compound.
Step 2. Using a curved arrow to shift the C1=C2 pi electrons onto C1, and a second curved arrow to shift the C3=C4 pi electrons to form a new C2=C3 pi bond, generates a resonance structure with a NEGATIVE charge on C1 (now bearing a lone pair) and a POSITIVE charge on C4 (now electron deficient), with the double bond shifted to sit between C2 and C3. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.