Skip to content
Exercises · 14.33

Q.
  1. Draw all the no-bond resonance structures of isopropyl carbocation.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
80% · 33/41 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Identify the α-carbons and α-hydrogens. In (CH3)2CH⊕, the cationic carbon carries two attached (alpha) methyl groups, each contributing 3 hydrogens -- 6 α-hydrogens in total.

Step 2. Draw the no-bond resonance structures (section 14.6.8's method, as worked for ethyl cation). For EACH of these 6 α C-H bonds in turn, one no-bond resonance structure is drawn showing that specific C-H bond as broken (no bond between that particular carbon and that particular hydrogen), its electron pair delocalised into the cationic carbon's empty p-orbital (forming a partial pi-type overlap), and that specific hydrogen shown migrating outward as if it were now a bare, loosely-associated proton -- while the other 5 α-hydrogens remain ordinary, intact C-H bonds in that particular contributing structure. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.