Exercises · 14.18
Q.B. Benzaldehyde
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Start your 14-day free trial to unlock the full solution →Step 1. Benzaldehyde, C6H5-CHO, carries a carbonyl group directly conjugated to the ring -- exactly the -R-withdrawing behaviour section 14.6.6 assigns to -CHO.
Step 2. Drawing the ring pi electrons shifting toward the electron-withdrawing carbonyl (curved arrows from the ring into the C=O system) generates a resonance structure with a formal positive charge on an ORTHO ring carbon and a formal negative charge on the carbonyl oxygen.
Step 3. A second such shift instead places the positive charge on the PARA ring carbon (again with negative charge on the carbonyl oxygen). …
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