Exercise · Q26
Q.Choose the correct option.
1-Chloropropane on treatment with alc. KOH produces:
a. propane b. propene c. propyne d. propyl alcohol
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Start your 14-day free trial to unlock the full solution →Step 1. Identify the reagent and reaction type. Alcoholic KOH, applied to an alkyl halide, is specifically the dehydrohalogenation (elimination) condition of section 15.2.2 -- it removes H and X from adjacent carbons to form an alkene, rather than substituting the halogen (which would need AQUEOUS KOH instead).
Step 2. Apply to 1-chloropropane. 1-Chloropropane is CH3-CH2-CH2-Cl; eliminating H (from C2) and Cl (from C1) with hot alcoholic KOH gives propene, CH3-CH=CH2, plus KCl and H2O. …
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