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Exercise · Q37

Q.Name the following: What is the action of following on ethyl iodide?
a. alc, KOH b. Zn, HCl

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Step 1. Action of alc. KOH. As in section 15.2.2, hot alcoholic KOH on an alkyl halide is a dehydrohalogenation (elimination): CH3-CH2-I + KOH (alc.) gives CH2=CH2 (ethene) + KI + H2O.

Step 2. Action of Zn, HCl. As in section 15.1.3, zinc and dilute HCl generate nascent hydrogen that reduces the alkyl halide: CH3-CH2-I + 2[H] (from Zn, HCl) gives CH3-CH3 (ethane) + HI. …

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