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Exercise 7.3 · Q66

Q.Find the length of transverse axis, length of conjugate axis, the eccentricity, the co-ordinates of foci, equations of directrices and the length of latus rectum of the hyperbola 16x2−9y2=14416x^2 - 9y^2 = 144.

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16x2−9y2=144⇒x29−y216=116x^2-9y^2=144 \Rightarrow \dfrac{x^2}{9}-\dfrac{y^2}{16}=1. So a2=9, b2=16⇒a=3, b=4a^2=9,\,b^2=16 \Rightarrow a=3,\,b=4.

e2=1+169=259⇒e=53e^2=1+\dfrac{16}{9}=\dfrac{25}{9} \Rightarrow e=\dfrac53.

  • Transverse axis =6=6; conjugate axis =8=8.
  • Foci (±ae,0)=(±5,0)(\pm ae,0)=(\pm5,0).
  • Directrices x=±ae=±95x=\pm\dfrac{a}{e}=\pm\dfrac95.
  • Latus rectum =2b2a=323=\dfrac{2b^2}{a}=\dfrac{32}{3}.
✓Final answer

Transverse 66, conjugate 88, e=53e=\tfrac53, foci (±5,0)(\pm5,0), directrices x=±95x=\pm\tfrac95, latus rectum 323\tfrac{32}{3}.

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