Find the eccentricity of the hyperbola, which is conjugate to the hyperbola $x^2 - 3y^2 = 3$.

Find the eccentricity of the hyperbola, which is c – Class 11 Mathematics

Exercise 7.3 · Q75

x^2 - 3y^2 = 3

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$x^2-3y^2=3 \Rightarrow \dfrac{x^2}{3}-\dfrac{y^2}{1}=1$ , so $a^2=3,\,b^2=1$ .

Its conjugate hyperbola is $\dfrac{y^2}{1}-\dfrac{x^2}{3}=1$ , whose own semi-transverse-axis-squared is $1$ (the old $b^2$ ) and semi-conjugate-axis- …

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Q.Find the eccentricity of the hyperbola, which is conjugate to the hyperbola $x^2 - 3y^2 = 3$ .

Concept understanding — Focal Properties and Latus Rectum of a Hyperbola

Q.Find the eccentricity of the hyperbola, which is conjugate to the hyperbola x2−3y2=3x^2 - 3y^2 = 3x2−3y2=3.

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Q.Find the eccentricity of the hyperbola, which is conjugate to the hyperbola $x^2 - 3y^2 = 3$ .

Unlock everything free for 14 days